Given the root of a binary tree, return the sum of the values on the deepest level. All
nodes on the deepest level are leaves. Return 0 for an empty tree.
Examples
1
/ \
2 3
/ \ \
4 5 6
/ \
7 8
Input: root = build_tree([1, 2, 3, 4, 5, None, 6, 7, None, None, None, None, 8])
Output: 15
Explanation: the deepest level holds 7 and 8.
Input: root = build_tree([3, 9, 20, None, None, 15, 7])
Output: 22
Constraints
0 <= number of nodes <= 2000-10**4 <= node.val <= 10**4- Target complexity: O(n) time.
Goals
- Identify the last level of a level-order traversal
- Sum a level while it is being processed
- Handle chains where the deepest level has one node