Given a lowercase string s and queries [l, r, ch], return for each query how many times the letter ch occurs in s[l..r] inclusive.
Examples
Input: s = "mississippi", queries = [[0, 3, "s"], [4, 10, "i"], [0, 10, "p"], [2, 2, "m"]]
Output: [2, 3, 2, 0]
Explanation: "miss" holds two s; "issippi" holds three i; the whole word holds two p; s[2] is not m.
Input: s = "a", queries = [[0, 0, "b"]]
Output: [0]
Constraints
1 <= len(s) <= 2 * 10**4,0 <= len(queries) <= 10**50 <= l <= r < len(s),chis a single lowercase letter- Target complexity: O(26 * n + q). Counting inside each substring separately is too slow for the largest tests.
Goals
- Keep one prefix-count array per distinct letter
- Build prefix tables lazily so unused letters cost nothing